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Camsy
Team:
Main: PM Me If You Suck
Level: 1996 Class:
Gunner
Joined: Fri Nov 28, 2008 6:03 pm Location: Sydney, Australia
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Re: Official Homework Help Thread
it says the solution should look something like this: {(4z-2,3z-6,z)} where z is any real number =/
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Fri Nov 18, 2011 10:41 pm |
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SimonV2
Team:
Main: Si's_Yes_Man
Level: 2266 Class:
Fleet Commander
Joined: Tue Apr 05, 2005 7:27 pm
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Re: Official Homework Help Thread
anilv wrote: Row reduce to
[1,0, -6|-4] [0,1, -5|-5] [0, 0, 0 | 0]
Therefore, x - 6z = -4 and y - 5z = -5. Otherwise put,
x = -4 + 6z y = -5 + 5z {{6z-4, 5z-5, z}}
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Fri Nov 18, 2011 11:15 pm |
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Camsy
Team:
Main: PM Me If You Suck
Level: 1996 Class:
Gunner
Joined: Fri Nov 28, 2008 6:03 pm Location: Sydney, Australia
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Re: Official Homework Help Thread
SimonV2 wrote: anilv wrote: Row reduce to
[1,0, -6|-4] [0,1, -5|-5] [0, 0, 0 | 0]
Therefore, x - 6z = -4 and y - 5z = -5. Otherwise put,
x = -4 + 6z y = -5 + 5z {{6z-4, 5z-5, z}} I fucking love you both!!!! <3 Thanks Simon and Enk! ~Preter
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Fri Nov 18, 2011 11:23 pm |
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Visorak
Team:
Main: Radia
Level: 1101 Class:
Speed Demon
Joined: Wed Oct 10, 2007 6:04 pm Location: q3dm17
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Re: Official Homework Help Thread
Physics question!
A 4.65 kg mass is hung on a spring, and the spring stretches 11.4 cm in response. If the mass is then displaced an additional 5.0 cm and released, what is the period of its motion?
So my formula is T= 2pi * sqrt(m/k)
Where m is mass, and k is the spring force constant.
My trouble is not knowing exactly which numbers to use to find k.
if F= -k * x
then 46 N= -k * x
But what is x? 5 cm, 11.4 cm, or 16.4 cm?
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Mon Mar 12, 2012 12:52 am |
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treygrey1
Team:
Main: Xenodread
Level: 1289 Class:
Gunner
Joined: Mon Sep 29, 2008 2:43 pm Location: In a van, down by the river.
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Re: Official Homework Help Thread
If the spring is displaced away from the equilibrium, you need the sum of the displacement and the rest state with the weight. This means the total of the two. Also, looking at your formulae, I have noticed that your Newton measurement is incorrect.
That was my friend. Also, isn't one of your characters named Physic?
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Mon Mar 12, 2012 10:23 am |
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Visorak
Team:
Main: Radia
Level: 1101 Class:
Speed Demon
Joined: Wed Oct 10, 2007 6:04 pm Location: q3dm17
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Re: Official Homework Help Thread
Quote: If the spring is displaced away from the equilibrium, you need the sum of the displacement and the rest state with the weight. This means the total of the two. Also, looking at your formulae, I have noticed that your Newton measurement is incorrect. From the book I'm using, Force=mass*accel. Gravity is the acceleration, so 4.65kg*-9.8m/sec^2 = -45.5 N, which rounds to -46 N. I think the equilibrium is supposed to be at 11.4cm. The question is worded poorly, but I think the first and second sentences are separate. So, the mass is hung from a spring, comes to a rest and then is pulled down. Quote: That was my friend. Also, isn't one of your characters named Physic? Moderated.
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Jey123456 wrote: That will happen in a future closer than most futures. No Context. Ever. Idaten.
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Mon Mar 12, 2012 3:39 pm |
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